[ Leetcode ] 1476. Subrectangle Queries - Java

Implement the class SubrectangleQueries which receives a rows x cols rectangle as a matrix of integers in the constructor and supports two methods:

1. updateSubrectangle(int row1, int col1, int row2, int col2, int newValue)

• Updates all values with newValue in the subrectangle whose upper left coordinate is (row1,col1) and bottom right coordinate is (row2,col2).

2. getValue(int row, int col)

• Returns the current value of the coordinate (row,col) from the rectangle.

 

Example 1:

 
 Input ["SubrectangleQueries","getValue","updateSubrectangle","getValue","getValue","updateSubrectangle","getValue","getValue"] 
 [[[[1,2,1],[4,3,4],[3,2,1],[1,1,1]]],[0,2],[0,0,3,2,5],[0,2],[3,1],[3,0,3,2,10],[3,1],[0,2]] 
 Output [null,1,null,5,5,null,10,5] 
 Explanation 
 SubrectangleQueries subrectangleQueries = new SubrectangleQueries([[1,2,1],[4,3,4],[3,2,1],[1,1,1]]); 
 // The initial rectangle (4x3) looks like: 
 // 1 2 1 
 // 4 3 4 
 // 3 2 1 
 // 1 1 1 
 subrectangleQueries.getValue(0, 2); // return 1 
 subrectangleQueries.updateSubrectangle(0, 0, 3, 2, 5); 
 // After this update the rectangle looks like: 
 // 5 5 5 
 // 5 5 5 
 // 5 5 5 
 // 5 5 5 
 subrectangleQueries.getValue(0, 2); // return 5 
 subrectangleQueries.getValue(3, 1); // return 5 
 subrectangleQueries.updateSubrectangle(3, 0, 3, 2, 10); 
 // After this update the rectangle looks like: 
 // 5 5 5 
 // 5 5 5 
 // 5 5 5 
 // 10 10 10 
 subrectangleQueries.getValue(3, 1); // return 10 
 subrectangleQueries.getValue(0, 2); // return 5
 

Example 2:

 
 Input
 ["SubrectangleQueries","getValue","updateSubrectangle","getValue","getValue","updateSubrectangle","getValue"]
 [[[[1,1,1],[2,2,2],[3,3,3]]],[0,0],[0,0,2,2,100],[0,0],[2,2],[1,1,2,2,20],[2,2]]
 Output
 [null,1,null,100,100,null,20]
 Explanation
 SubrectangleQueries subrectangleQueries = new SubrectangleQueries([[1,1,1],[2,2,2],[3,3,3]]);
 subrectangleQueries.getValue(0, 0); // return 1
 subrectangleQueries.updateSubrectangle(0, 0, 2, 2, 100);
 subrectangleQueries.getValue(0, 0); // return 100
 subrectangleQueries.getValue(2, 2); // return 100
 subrectangleQueries.updateSubrectangle(1, 1, 2, 2, 20);
 subrectangleQueries.getValue(2, 2); // return 20
 

 

Constraints:

• There will be at most 500 operations considering both methods: updateSubrectangle and getValue.
• 1 <= rows, cols <= 100
• rows == rectangle.length
• cols == rectangle[i].length
• 0 <= row1 <= row2 < rows
• 0 <= col1 <= col2 < cols
• 1 <= newValue, rectangle[i][j] <= 10^9
• 0 <= row < rows
• 0 <= col < cols

 

Solution

 

 
 class SubrectangleQueries {

    int[][] rectangle;
    
    public SubrectangleQueries(int[][] rectangle) {
        this.rectangle = rectangle;
    }
    
    public void updateSubrectangle(int row1, int col1, int row2, int col2, int newValue) {
        for(int i=row1; i<=row2; i++){
            for(int j=col1; j<=col2; j++){
                this.rectangle[i][j] = newValue;
            }
        }
    }
    
    public int getValue(int row, int col) {
        return this.rectangle[row][col];
    }
 }

 /**
  * Your SubrectangleQueries object will be instantiated and called as such:
  * SubrectangleQueries obj = new SubrectangleQueries(rectangle);
  * obj.updateSubrectangle(row1,col1,row2,col2,newValue);
  * int param_2 = obj.getValue(row,col);
  */
  

1. 2차배열로 직사각형을 만든다 -> 생성자

2. for문인 경우 <row2+1보다는 <=row2가 더 효율적이다

 

24초.. 더 빠르게 할 방법을 찾아봐야겠다